prove that tan2A =2tanA /1-tan^2A
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tan (2A) = sin(2A) / cos(2A)
= 2 sinA cos A / (cos^2 A - sin^2 A)
Divide numerator and denominator by cos^2 A...
= 2 (sinA / cosA) / (1-[sinA / cosA]^2)
= 2 tanA / (1-tan^2 A)
Answered by
19
tan (2A) = sin(2A) / cos(2A)
= 2 sinA cos A / (cos^2 A - sin^2 A)
Divide numerator and denominator by cos^2 A...
= 2 (sinA / cosA) / (1-[sinA / cosA]^2)
= 2 tanA / (1-tan^2 A)
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