Question

Prove that
tan²A+ cot²A+ 2 = sec²A+ cosec²A​

Answer 1

Answer:

the answer for the question is

Answer 2

Answer:

L.H.S

$\implies tan^{2}A+cot^{2}A \\ \implies yan^{2}+cot^{2}+1+1 \\ \implies tan^{2}+1+xot^{2}A+1$

since, $\implies tan^{2}A+1 = sec^{2}A \\ and \: cot^{2}A+1= cosec^{2}A$

$\implies sec^{2}A+cosec^{2}A$

$\implies \frac{1}{cos^2A} + \frac{1}{sin^2 }A$

$\implies \frac {sin^2+ cos^2}{cos^2A sin^2A}$

$\implies \frac{1}{cos^2sin^2} \\ \implies sec^{2} cosec^{2}.=R.H.S$