Math, asked by MARK0007, 7 months ago

prove that Tan²A Sec²B -Tan²B Sec²A = tan²A-tan²B

Answers

Answered by yogeet

1

Step-by-step explanation:

RHS =tan²Asec²B-tan²Bsec²A

=tan²A(1-tan²B)-tan²B(1-tan²A)

=tan²A-tan²Atan²B-tan²B+tan²Atan²B

=tan²A-tan²B

Answered by nkeerthana456

1

Answer:

To prove that Tan²A Sec²B -Tan²B Sec²A = tan²A-tan²B

Proof:

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