prove that Tan²A Sec²B -Tan²B Sec²A = tan²A-tan²B
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Step-by-step explanation:
RHS =tan²Asec²B-tan²Bsec²A
=tan²A(1-tan²B)-tan²B(1-tan²A)
=tan²A-tan²Atan²B-tan²B+tan²Atan²B
=tan²A-tan²B
Answered by
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Answer:
To prove that Tan²A Sec²B -Tan²B Sec²A = tan²A-tan²B
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