Question

Prove that tan2a-tan2b=sin2a-sin2b/cos2a.sin2b

Answer 1

Answer:

no we can't prove tan 2a-tan 2b=sin2a-sin 2b/cos 2a.Sin2b

Step-by-step explanation:

subsitute any degree in the given question check whether LHS=RHS

let take a=15 and b=30 degrees

tan2(15)-tan2(30)=Sin2(15)-Sin2(30)/cis2(15)sin2(30)

tan30- tan 60=Sin 30- Sin 60/ Cos 30 Sin 60

1 /3^1/2 -3^1/2= 1/2-3^1/2 /2 /3/4

2/3^1/2 = 1-3^1/2/4

therefore LHS is not equal to RHS

we cannot prove