Prove that tan²teta-1 by
tan²teta +1
= =1-2cos² tete
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Here LHS =
tan²∅-1
tan²∅+1
sin²∅ - 1
= cos²∅
sin²∅ +1
cos²∅
sin²∅-cos²∅
cos²∅
= sin²∅+cos ²∅
cos²∅
= sin²∅-cos²∅
sin²∅+cos²∅
= (1-cos²∅)-cos²∅
1
= 1-cos²∅-cos²∅
= 1-2cos²∅
Applied formulas
tan∅= sin∅/cos∅
sin²∅+cos²∅=1
or
cos²∅= 1-sin²∅
or
sin²∅= 1-cos²∅
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