Math, asked by sreevatsava12, 11 months ago

prove that tan³θ/1+tan²θ+cot³θ/1+cot²θ=secθcosecθ-2sinθcosθ.

Answers

Answered by sandy1816

3

Step-by-step explanation:

tan³A/1+tan²A + cot³A/1+cot²A

=tan³A/sec²A + cot³A/cosec²A

=sin³A/cosA + cos³A/sinA

=(sin⁴A+cos⁴A)/sinAcosA

={sin²A+cos²A}²-2sin²Acos²A/sinAcosA

=1-2sin²Acos²A/sinAcosA

=secAcosecA-2sinAcosA

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