Prove that
tan⁴A+tan²A=sec⁴A-sec²A
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Answered by
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Hi friend!!
LHS = tan⁴A+tan²A
= tan²A(tan²A+1)
= tan²A(sec²A)
= (sec²A-1)sec²A
= sec⁴A-sec²A
= RHS
Hence proved.
LHS = tan⁴A+tan²A
= tan²A(tan²A+1)
= tan²A(sec²A)
= (sec²A-1)sec²A
= sec⁴A-sec²A
= RHS
Hence proved.
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