Question

prove that tan50°-tan40°=2tan10°​

Answer 1

Answer:

$rhs :-\\2 tan 10 =2 \frac{tan 50 - tan 40}{1 + tan40 tan 50} \\2\frac{tan 50 - tan 40}{1 + tan(90-40)tan40} \\2\frac{tan 50 - tan 40}{1 + cot40 tan40}\\ (tan 50 - tan 40)$

Step-by-step explanation:

cot x. tan x = 1

tan (90- x) = cot x

tan (x-y)= (tan x - tan y )/(1+ tan x tan y)