Question

Prove that (tan60)^2-(cos60)^2/tan45(sin60)^2 = 11/3

Answer 1

Step-by-step explanation:

Here LHS:-

=(tan60)^2-(cos60)^2/tan45(sin60)^2

=[(root 3)^2-(1/2)^2]/1(root 3/2)^2

=[3-1/4]/3/4

=(11/4)/(3/4)

=11/3

Hence proved.

Answer 2

Answer:

solved.

Step-by-step explanation:

1. first, see the values of the functions.

tan60 = √3 cos60 = 1/2

tan45 = 1 sin60 = √3/2

2. now, (tan60)^2 = (√3)^2 = 3

(cos60)^2 = ( 1/2 )^2 = 1/4

tan45 = 1

(sin60)^2 = (√3/2 )^2 = 3/4

3. put all this values in equation.

4. ( 3-1/4 ) / 1× 3/4 = ( 11/4 ) / (3/4 ) = 11/3

5. hence proved