Question

Prove that tan7 tan23 tan60 tan67 tan83=√3

Answer 1

Answer:

Given, tan7°tan23°tan60°tan67°tan83°

= tan(90°-83°)tan83°tan(90-67°)tan67°tan60°

= cot83°tan83°cot67°tan67°tan60°

= (1/tan83°) × tan83° × (1/tan67°) × tan67°× tan60°

= 1 × 1 × tan60°

= √3 (ans.)Step-by-step explanation:

Answer 2

u rearrange it first

tan7tan83 tan23tan67 and tan60

then all become 1 except tan 60 which is root 3 hence 1×√3 is √3