Question

Prove that
tan75°+cot75°=4​

Answer 1

Step-by-step explanation:

LHS

tan 75= tan(45+30)

now using tan(a+b)= (tan a + tan b)/1-tan a tan b

tan 75= [1+(1/√3)]/1-(1/√3)

tan 75= (√3+1)/(√3-1)....1

cot 75 = 1/tan 75

cot 75= (√3-1)/(√3+1)....2

adding 1 and 2

[(√3+1)^2+(√3-1)^2]/(√3+1)(√3-1)

(3+1+2√3+3+1-2√3)/(3-1)

8/2

4= RHS

HENCE PROVED

HOPE IT HELPS U

MARK AS BRAINLIEST