Math, asked by anonymous1763, 5 hours ago

prove that
tan8θ -tan6θ-tan2θ = tan8θ.tan6θ.tan2θ

Answers

Answered by jissj267

0

Step-by-step explanation:

LHS=tan8θ−tan6θ−tan2θ

We know tan(8θ−6θ)=

1+tan8θ+tan6θ

tan8θ−tan6θ

⇒tan8θ−tan6θ=tan2θ(1+tan8θtan6θ)

LHS=tan2θ(1+tan8θtan6θ)−tan2θ

=tan2θ+tan2θtan8θtan6θ−tan2θ

=tan8θ.tan6θtan2θ

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