Prove That----. tanA/(1-cotA) + cotA/(1-tanA) = 1 + secAcosecA
pls solve very urgent
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Heya,
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=(sinA/cosA)/((sinA-cosA)/sinA) + (cosA/sinA)/((cosA-sinA)/cosA)
=(sinA)^2 / cosA(sinA-cosA)-(cosA)^2/sinA(sinA-cosA)
=1/(sinA-cosA) * [(sinA)^2/cosA-(cosA)^2/sinA]
=1/(sinA-cosA) * [((sinA)^3-(cosA)^3)/sinA*cosA]
=1/(sinA-cosA) * [(sinA-cosA)((sinA)^2+(cosA)^2+sinA*cosA...
=(1+sinA*cosA)/sinA*cosA
=1+ cosecA * secA
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=(sinA/cosA)/((sinA-cosA)/sinA) + (cosA/sinA)/((cosA-sinA)/cosA)
=(sinA)^2 / cosA(sinA-cosA)-(cosA)^2/sinA(sinA-cosA)
=1/(sinA-cosA) * [(sinA)^2/cosA-(cosA)^2/sinA]
=1/(sinA-cosA) * [((sinA)^3-(cosA)^3)/sinA*cosA]
=1/(sinA-cosA) * [(sinA-cosA)((sinA)^2+(cosA)^2+sinA*cosA...
=(1+sinA*cosA)/sinA*cosA
=1+ cosecA * secA
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Vanquisher:
thanks but can u do me a favour.... pls
wht/
can u write it somewhere properly take a pic and then send it to me
i cant uderstand the proof
what u have written
pls write on a paper and then take a pic and send to me pls pls pls
now is it clear?
thanks
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