Question

prove that tanA+CotA= sinA.CosecA

Answer 1

  tanA + cotA = sinA/cosA + cosA/sinA
= (sin²A + cos²A) / cosA.sinA
= 1 / cosA.sinA
= secA.cosecA

Answer 2

 tanA + cotA

= $\frac{sinA}{cosA}+\frac{cosA}{sinA}$

= $\frac{(sin^{2}A + cos^{2}A)}{cosA.sinA}$

=$\frac{1}{cosA.sinA}$

= $secA.cosecA$  PROVED