Math, asked by aditya3214, 9 months ago

prove that
tanA/secA-1=secA+1/tanA​

Answers

Answered by spiderman2019
0

Answer:

Step-by-step explanation:

TanA/SecA - 1

Multiply numerator and denominator by SecA + 1

=> TanA/SecA - 1  * SecA + 1 / SecA + 1

=> TanA(SecA + 1) / (SecA - 1)(SecA + 1)

=> TanA(SecA + 1) / Sec²A - 1

=> TanA(SecA + 1) / Tan²A  (∵ Sec²A - 1 = TanA)

=> SecA + 1 / TanA

= R.H.S

Hence proved

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