prove that
tanA /secA +1 +secA +1 /tanA = 2 cosecA
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Step-by-step explanation:
tanA/secA+1 + secA+1/tanA
=tan²A+(secA+1)²/tanA(secA+1)
=tan²A+sec²A+1+2secA/tanA(secA+1)
=2secA(secA+1)/tanA(secA+1)
=2secA/tanA
=2.1/cosA×cosA/sinA
=2/sinA
=2cosecA
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