Math, asked by op94220, 9 months ago

prove that
tanA /secA +1 +secA +1 /tanA = 2 cosecA

Answers

Answered by sandy1816
1

Step-by-step explanation:

tanA/secA+1 + secA+1/tanA

=tan²A+(secA+1)²/tanA(secA+1)

=tan²A+sec²A+1+2secA/tanA(secA+1)

=2secA(secA+1)/tanA(secA+1)

=2secA/tanA

=2.1/cosA×cosA/sinA

=2/sinA

=2cosecA

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