Question

prove that... tanA +secA -1/tanA-secA+1=1+sinA/cosA?​

Answer 1

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Here is ur answer

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Answer 2

Answer:

Step-by-step explanation:

first of all change everything in terms of sin and cos...

tan A + SEC A - 1 / TAN A - SEC A +1

=> (SEC A + TAN A ) - 1 / (TAN A - SEC A) + 1

=> (SEC A + TAN A ) - (SEC ^ 2 A - TAN^ 2 A ) / TAN A - SEC A + 1

=> (SEC A + TAN A) + [ (SEC A + TAN A ) ( SEC A - TAN A ) ] / TAN A - SEC A +1

=> (SEC A + TAN A) [ 1 - ( SEC A - TAN A ) / TAN A - SEC A + 1

=> ( SEC A + TAN A ) (1 + TAN A - SEC A ) / 1 + TAN A - SEC A

=> SEC A + TAN A  => 1 / COS A + SIN A / COS A

=> 1 + SIN A / COS A

LHS = RHS

HENCE PROVED...