Math, asked by chahat492, 1 year ago

Prove that:
(tanA+secA-1)/(tanA-secA+1)=(1+sinA)/cosA​

Answers

Answered by dhruvbadaya1
1

To prove:

( tanA + secA -1)/( tanA- secA+1) = (1+sinA)/cosA

Proof:

LHS= (tanA - secA) - (sec2A - tan2A)/tanA + 1 - secA

=>(tanA - secA) (1 - (secA - tanA))/tanA + 1 - secA

=>(tanA - secA) (1 - secA + tanA)/tanA + 1 - secA

=>sec A + tan A

=>1/cosA + sinA/cosA

=>1 + sinA/cosA =RHS

Hence, Proved.

Answered by sandy1816
0

Answer:

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