Prove that:
(tanA+secA-1)/(tanA-secA+1)=(1+sinA)/cosA
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To prove:
( tanA + secA -1)/( tanA- secA+1) = (1+sinA)/cosA
Proof:
LHS= (tanA - secA) - (sec2A - tan2A)/tanA + 1 - secA
=>(tanA - secA) (1 - (secA - tanA))/tanA + 1 - secA
=>(tanA - secA) (1 - secA + tanA)/tanA + 1 - secA
=>sec A + tan A
=>1/cosA + sinA/cosA
=>1 + sinA/cosA =RHS
Hence, Proved.
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