Prove that tanA+secA-1/tanA-secA+1=1+sinA/cosA
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Step-by-step explanation:
tanA-1+secA/tanA+1-secA
(tan A+secA)-(sec^2-tan^2A)
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tan A+1-secA
(tanA+secA)(1-secA+tanA)
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tanA+1-secA
(tanA-secA)(1-secA+tanA)
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tan A+1-secA
SecA+tanA
1/cos A + sinA/cosA
1+sinA/cos A
Done †
Anonymous:
good job ....
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