Math, asked by Amishh3659, 8 months ago

Prove that (tanA +secA -1)/(tanA -secA+1 )=tanA+secA

Answers

Answered by sandy1816

4

Step-by-step explanation:

tanA+secA-1/tanA-secA+1

=(tanA+secA)-(sec²A-tan²A)/(tanA-secA+1)

=(tanA+secA)-(secA-tanA)(secA+tanA)/(tanA-secA+1)

=(tanA+secA)(1-secA+tanA)/(tanA-secA+1)

=tanA+SecA

Answered by hemantabaruah23

0

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