Question

prove that (tanA×sinA)+cos A =sec A​

Answer 1

Answer:

tanA=sinA/cosA

(sinA/cosA×sinA)+cosA

(sin^2A/cosA)+cosA

(sin^2A+cos^2A/cosA)

(1/cosA)=secA....

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Answer 2

Answer:

SEC A

Step-by-step explanation:

=(sin A/cos A×sinA)+cos A

=(sin²A/COS A)+cos A

∴ on TAKING l.c.m OF COS A AND 1:-

=sin²A+cos²A/cos A

=1/cos A                                   [∵ sin²A+ cos²A  =1]

=secA

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