Question

prove that ,tanA+sinA/tanA-sinA=secA+1/secA-1​

Answer 1

Answer:

(tanA + sinA)/(tanA - sinA)

=(sinA/cosA + sin A)/(sinA/cosA - sinA)

=((sinA + sinAcosA)/cosA)/((sinA - sinAcosA)/cosA)

=(sinA(1+cosA))/(sinA(1-cosA))

=(1+cosA)/(1-cosA)

=(1+(1/secA))/(1-(1/secA))

=((secA + 1)/secA)/((secA-1)/secA)

=(secA+1)/(secA-1)

Step-by-step explanation:

Answer 2

Hi there !!

Have many methods to do these type of questions.

• Identity used :-

• sinA.cosecA = 1

• cosA = 1/secA

• tanA = sinA/cosA

Look at the attachment ↑↑

Thankyou :)