Question

prove that tanA × sinA÷tanA+sinA= tanA -sinA ÷tanA× sinA​

Answer 1

Answer:

As sec

2

A−tan

2

A=1⇒secA=±

tan

2

A+1

=±

16

9

+1

=±

16

25

=±

4

5

⇒cosA=

secA

1

=±

5

4

And sin

2

A+cos

2

A=1

⇒sinA=±

1−cos

2

A

=±

1−

25

16

=±

25

9

=±

5

3

⇒sinAcosA=

25

12