Math, asked by angokul2006, 7 months ago

prove that tanA+tanB/CotA+CotB=tanA tanB

Answers

Answered by jakbattu

2

Step-by-step explanation:

LHS = tanA+tanB/CotA+CotB

= tanA+tanB / 1/tanA+1/tanB

= tanA+tanB / tanA+tanB)/tanAtanB

= 1 / 1 / tanAtanB

= tanAtanB = RHS

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