Prove that tanA-tanB/
CotA-cotB =tanB/cotA
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Step-by-step explanation:
ANSWER
LHS=
cotB+tanA
cotA+tanB
=
tanB
1
+tanA
tanA
1
+tanB
=
tanB
1+tanAtanB
tanA
1+tanAtanB
=
tanA
tanB
=cotAtanB=RHS
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