Question

Prove that tanA + tanB + tanC+ tanD =0

Answer 1

Answer:

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Step-by-step explanation:

$\sin(a) + \cos(a ) = \tan(a) ......(1) \\ \sin(b) + \cos(b) = \tan(b) ............(2) \\ \sin(c) + \cos(c) = \tan(c) .............(3) \\ \sin(d) + \cos(d) = \tan(d) ..............(4) \\ from \: eq.1.2.3.4 \\ \tan(a) + \tan(b) + \tan(c) + \tan(d) = 0.....(0 \: is a \: constant).$