Question

prove that tanB+c/2=cotA/2​

Answer 1

Step-by-step explanation:

Let three angles of a triangle be ABC

A+B+C=180°

B+C=180°-A

Divide by 2

=>B+C/2=90°-A/2

Multiply both the sides by tan

=>tan B+C/2 = tan(90°-A/2)

=tan B+C/2=cot(A/2)

Hence proved