Question

Prove that tangent Dewan from an external point are equal

Answer 1

Answer:

☆ANSWER☆

GIVEN :

OA = OB

< OAP = <OBP =90

TO PROVE :

PA = PB

PROOF :

IN TRIANGLE AOP AND BOP

OA = OB (GIVEN)

< OAP = < OBP =90 ( GIVEN)

PO = PO ( COMMON)

THEREFORE ,

TRIANGLE AOP AND BOP ARE CONGRUENT BY RHS CONGREUNCY RULE.

THEREFORE ;

BY C.P.C.T.

PA = PB

HOPE THAT HELPS

#ANSWERWITHQUALITY