Question

prove that tangents drawn from the circle from external point are equal​

Answer 1

Answer:

☆ANSWER☆

GIVEN :

OA=OB

<OAP= <OBP = 90

TO PROVE /FIND :

PA = PB

PROOF :

IN TRIANGLE AOP AND BOP

OA=OB (GIVEN)

PA=PA (COMMON)

<OAP=<OBP= 90 (GIVEN)

THEREFORE

TRIANGLE AOP AND BOP ARE CONGRUENT BY RHS CONGRUENCY.

BY C.P.C.T.

PA=PB

HOPE THAT HELPS

# ANSWERWITH QUALITY

Answer 2

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