prove that tangents to a circle at a point of a diameter or parallel
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Step-by-step explanation:
Prove that the tangents drawn at the end of a diameter of a circle are parallel. Given: A circle with centre O and diameter AB. Let PQ be the tangent at point A & Rs be the point B. ... OA⊥ PQ(Tangent at any point of circle is perpendicular to the radius through point of contact
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Answered by
1
Step-by-step explanation:
OA is perpendicular to MN
OB is also perpendicular to QP
<OAM=90°
<OAN=90°
<OBQ=90°
<OAM=<OBP(alternate angles)
<OAN=<OBQ(alternate angles))
Interior two angles are alternate, so MN//QP
Hence proved
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