Question

prove that tano+sec 0-1/
tano - sec 0+1=1+sino/coso​

Answer 1

To Prove

→ (tan∅ + sec∅ - 1)/(tan∅ - sec∅ + 1) = (1 + sin∅)/cos∅

Proof

(Given in the attachment)

Procedure

Identities used in solution

• tan∅ = sin∅/cos∅

• sec∅ = 1/cos∅

• (sin∅ + 1)² = sin²∅ + 1 + 2sin∅

• (sin∅ + cos∅) = sin²∅ + cos²∅ + 2sin∅cos∅

• sin²∅ + cos²∅ = 1

• cos²∅ = (1 - sin²∅)

Since we got L.H.S = R.H.S

Hence Proved

Answer 2

Answer:

I d o n t k n o w p l s a n s w e r m e