Question

prove that tantheta + tan(90-theta)=sectheta×sec(90-theta)​

Answer 1

tan a+tan(90-a)==>tan a+cot a[tan(90-a)=cot a)

=(sin a/cos a)+(cos a/sin a)

=(sin^2a+cos^2a)/sin.cos a

=1/sin.cos a

=(1/sin a)(1/cos a)

=cosec a*sec a[1/sin a=cosec a,1/cos=sec a]

=sec a*sec(90-a)(cosec a=sec(90-a))