Question

prove that tanx+cotx=2cosec2x​

Answer 1

Step-by-step explanation:

$\tan \: x \: + \cot\: x \: = 2 \csc \: 2x$

$\frac{ \sin \: x }{ \cos \: x } = \tan \: x$

$\frac{cos \: x}{tan \: x} = cot \: x$

$\frac{sin \: x}{cos \: x} + \frac{ \cos \: x }{tan \: x} = 2 \: cosec \: 2x$

LHS :

$\frac{ (\sin \: x)(tan \: x \: ) + (cos \: x \: cos \: x) }{(cos \: x \: )(tan \: x)}$

$\frac{(sin \: x)( \frac{sin \: x}{cos \: x} ) + (cos \: x \: cos \: x)}{(cos \: x)( \frac{sin \: x)}{cos \: x} )}$

I'm sryy i don't know how to conclude...

Answer 2

Answer:

hey mate please refer to the attachment