Prove that tanx + cotx can never be equal to 3/2
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Answered by
46
tanx + cotx = sinx/cosx+cosx/sinx.
=(sin^2x+cos^2x)/sinx×cosx
=1/sinx×cosx.
so,this can not be 3/2 as it is in the form 1/q,where q = sinx×cosx.
=(sin^2x+cos^2x)/sinx×cosx
=1/sinx×cosx.
so,this can not be 3/2 as it is in the form 1/q,where q = sinx×cosx.
Answered by
14
Answer:
Step-by-step explanation:
Tan x +cot x = (sin^2×+cos^2×)1/sinxcosx
1/sinx cosx as it is in the form of p/q and q=sinxcosx which can never be equal to 3/2
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