Math, asked by ahiranakinchana, 1 year ago

prove that
1 \div  \sqrt{2 }  \: is \: irrational

Answers

Answered by Brendancrawford
4

proof that the square root of 2 is irrational. Let's suppose √2 is a rational number. Then we can write it √2 = a/b where a, b are whole numbers, b not zero. We additionally assume that this a/b is simplified to lowest terms, since that can obviously be done with any fraction.

Answered by Anonymous
4
\textbf{\huge{ANSWER:}}

\sf{To\:Prove:}

\frac{1}{\sqrt2}\\

As we know, \sqrt2 is irrational.
Any integer divided by an irrational number is also irrational.

Due to this reason only, the number will be irrational.

\frac{1}{\sqrt2}\\ is \textbf{irrational}.

Hope it Helps!! :)
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