Question

prove that
${2}^{30} + {2}^{29} + {2}^{28} \div {2}^{31} + {2}^{30} + {2}^{29} = 7 \div 10$
please be fast

Answer 1

HELLO DEAR,

(2^30 + 2^29 + 2^28) / (2^31 + 2^30 + 2^29)

=> 2^28(2² + 2 + 1) / 2^28(2³ + 2² + 2)

=> (4+2+1)/(8+4+2)

=> 7/14

=> 1/2