Question

Prove that
$2and \: - 3 \: are \: the \: zeroes \: of \: polynomial \:q \: (x) = {x}^{2} + x - 6$
​

Answer 1

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

x^2 + x - 6

x^2 + (3-2)x - 6

x^2 + 3x - 2x - 6

x ( x + 3) - 2 ( x + 3 )

(x - 2) (x + 3)

x = 2 ,-3

hence proved

hope this helps u dear..