Math, asked by Anonymous, 11 months ago

Prove that ({3}^{2n}+7) is a multiple of 8.



✔️✔️ quality answer needed✔️✔️


❌❌NO SPAMMING❌❌​

Answers

Answered by phoenix1261
3

hlo mate !!

⤵️⤵️⤵️

The reason why that I was confused in this problem was because my steps has gotten me nowhere useful as shown below:

(I've omitted the words for the inductive proof for the sake of simplicity)

=32(k+1)−1

=9−32k−1

=8−9∗3k

But this has gotten me nowhere and I was wondering if there was any other way to prove this with inductive proof.

PLZ MARK ME


Anonymous: copied answers
phoenix1261: no yrrr
phoenix1261: from book
Anonymous: it must be deleted
phoenix1261: why
phoenix1261: reason
phoenix1261: thanx yrr
Answered by cutiebug
0

SOLUTION

hello mate !!

here is your answer

=32(k+1)−1

=9−32k−1

=8−9∗3k

Similar questions