Question

prove that
$3 + \sqrt{2}$
is an irrational​

Answer 1

Answer:

3√2 is an irrational number.

Step-by-step explanation:

Let us assume that 3√2 is a rational number.

So,we can represent it in p/q form.

Let a and b be two co prime number such that

3√2=a/b

√2=a/3b

Clearly,3,a,b are integer

So,a/3b is a rational number and√2 is an irrational number.

Also,a rational number can never be equal to an irrational number.

So,we conclude that 3√2 is an irrational number.

Answer 2

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