Prove that,
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Answered by
1
Step-by-step explanation:
a^m= is a multiplied m times
so if m is 0 then it means a is not multiplying and does not exist even in single as it doesn't has power 1 so it proves a^0=1
Answered by
3
Answer:
proof.....
x {}^{0} = 1x0=1
x {}^{1 - 1} = 1x1−1=1
x {}^{0} = x {}^{1} \times x {}^{ - 1}x0=x1×x−1
x {}^{0} = x \times \frac{1}{x}x0=x×x1
x {}^{0} = 1x0=1
Proved.
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