Question

Prove that,
$a^{0} = 1$
​

Answer 1

Step-by-step explanation:

a^m= is a multiplied m times

so if m is 0 then it means a is not multiplying and does not exist even in single as it doesn't has power 1 so it proves a^0=1

Answer 2

Answer:

proof.....

x {}^{0} = 1x0=1

x {}^{1 - 1} = 1x1−1=1

x {}^{0} = x {}^{1} \times x {}^{ - 1}x0=x1×x−1

x {}^{0} = x \times \frac{1}{x}x0=x×x1

x {}^{0} = 1x0=1

Proved.

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