Math, asked by gbiju37, 1 month ago

Prove that,
(a ^{2}  - b^{2} )^{3}  + ( {b}^{2}  -  {c}^{2}) ^{3}   + ( {c}^{2}  -  {a}^{2} ) ^{3}  = 3(a + b)(b + c)(c + a)(a - b)(b - c)(c - a)
please help me ​

Answers

Answered by Anonymous
2

Answer:

(-3)³ × (-3)⁴ = [(-3) × (-3) × (-3)] × [(-3) × (-3) × (-3) × (-3)]

= (-3)3+4

= (-3)⁷

4. m⁵ × m³ = (m × m × m × m × m) × (m × m × m)

= m5+3

= m⁸

From the above examples, we can generalize that during multiplication when the bases are same then the exponents are added.

Answered by ᏢerfectlyShine
37

Answer:

thanks ki jarurat nhi hai and plz intro do apna

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