Question

Prove that :

$\bf \frac{tan \: \theta \: + \: sec \: \theta - 1}{tan \: \theta \: - \: sec \: \theta \: + 1} = \frac{1 + sin \: \theta}{cos \: \theta}$

Answer 1

hey mate
refer to attachment

Answer 2

Step-by-step explanation:

see the attached image above.....

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