Question

PROVE THAT:





$Cos(\frac{\pi}{2} - θ)=Sinθ$
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Answer 1

Answer:

sorry g i dont know the answer of ur question..

Answer 2

$cos( \frac{\pi}{2} - \theta) = \sin( \theta) \\ = \cos( \frac{\pi}{2} ) . \cos( \theta) + \sin( \frac{\pi}{2} ) . \sin( \theta) \\ ....{ cos(a - b) = \cos(a). \cos(b) + \sin(a) . \sin(b) } \\ = 0. \cos( \theta) + 1. \sin( \theta) \\ ...{ \cos( \frac{\pi}{2} ) = 0} \: and \: \sin( \frac{\pi}{2} ) = 1 \\ = 0 + \sin( \theta) \\ = \sin( \theta)$