prove that:
![\frac{(1+cotθ+tanθ)(sinθ-cosθ)}{sec^{3} θ- {cosec}^{3} θ} = {sin}^{2} θ {cos}^{2} θ \frac{(1+cotθ+tanθ)(sinθ-cosθ)}{sec^{3} θ- {cosec}^{3} θ} = {sin}^{2} θ {cos}^{2} θ](https://tex.z-dn.net/?f=+%5Cfrac%7B%281%2Bcot%CE%B8%2Btan%CE%B8%29%28sin%CE%B8-cos%CE%B8%29%7D%7Bsec%5E%7B3%7D+%CE%B8-++%7Bcosec%7D%5E%7B3%7D+%CE%B8%7D+++%3D++%7Bsin%7D%5E%7B2%7D+%CE%B8+%7Bcos%7D%5E%7B2%7D+%CE%B8)
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