Question

prove that $\frac{1}{\sqrt{3} +\sqrt{7} } +\frac{1}{\sqrt{7}+\sqrt{5} } +\frac{1}{\sqrt{5}+\sqrt{3} } +\frac{1}{\sqrt{3}+1 } =1$

Answer 1

Answer:

Statement wrong

The first term must be

$\frac{1}{ \sqrt{9} + \sqrt{7} }$