Question

prove that
$\frac{1 + tan \alpha }{ \sec( \alpha ) ?} - \frac{ \sec( \alpha ) }{1 + \tan( \alpha ) } = \frac{2 \sin( \alpha \times \cos( \alpha ) ) }{ \sin alpha + \cos( \alpha ) ) }$
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Answer 1

Answer:

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Answer 2

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