CBSE BOARD X, asked by prover, 11 months ago

Prove that
 \frac{2}{5}  <  log_{10}(3)  <  \frac{1}{2}
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Answers

Answered by Anonymous
47

Answer:

 \frac{2}{5} < log_{10}(3) < \frac{1}{2}

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Answered by Anonymous
5

Answer:

2/5= 0.4

log(base10)3

=0.47

1/2

0.5

hence

0.5>0.47>0.4

so

1/2>log3>2/5

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