Question

Prove that
$\frac{3}{2 \sqrt{5} }$
is irrational.
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Answer 1

Hello ,

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$let \: \frac{3}{ \sqrt[2]{5} } is \: an \: rational \: number \\ \\ \frac{3}{ \sqrt[2]{5} } = \frac{a}{b} \\ \sqrt[2]{5} = \frac{3b}{a} \\ \\ integer = fraction \\ \\ \\ so \: our \: assumption \: is \: wrong \\ \\ \: \frac{3}{ \sqrt[2]{5} } is \: an \: irrational \: number$

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