Math, asked by VRU, 1 year ago

Prove that $\frac{sinФ - cosФ + 1 }{sinФ+cos Ф-1} =\frac{1}{secФ-tanФ}$ , using the identity sec²Ф= 1+tan²Ф

Answers

Answered by dheerajkrishna

In LHS divide each term by cosФ
then the 1 you get in denominator change it into sec²Ф-tan²Ф
write sec²Ф-tan²Ф in the form of (secФ-tanФ) and (secФ+tanФ)
so on solve it

kvnmurty: u have to do it and show. not just an advice.

dheerajkrishna: ok sir but i dont know how to type the symbols of mahts

kvnmurty: there is a button with Pi symbol on it, when are in the answering window. Next to that you have T button and Omega button too. Click on Pi to get equation editor.

Previous Question

Next Question

Prove that, using the identity sec²Ф= 1+tan²Ф

Answers

Prove that $\frac{sinФ - cosФ + 1 }{sinФ+cos Ф-1} =\frac{1}{secФ-tanФ}$ , using the identity sec²Ф= 1+tan²Ф