Question

Prove that $J_{n+1} (x)+J_{n-1} (x)=\frac{2n}{x} J_{n}(x)$.

Answer 1

The flowing liquid will always be very nearly pure solvent S. The product rho*Das can be considered constant, and the diffusion of A in S can be considered by a steady state version of the the continuity equation in terms of molar concentration (equation B.11.2). Note that the presence of a small amount of the reaction product B is ignored.